In the given figure an ammeter A consists of a $240 \Omega$ coil connected in parallel to a $10 \Omega$ shunt. The reading of the ammeter is $\qquad$ $\mathrm{mA}$

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Aicharya · Accepted Answer

Req $\begin{aligned} & =140.4+\frac{240 \times 10}{240+10} \\ & \text { Req }=140.4+\frac{2400}{250} \\ & \text { Req. }=150 \Omega \end{aligned}$ $\begin{aligned} \therefore \text { Current in ammeter } & =\frac{24}{150} \\ & =160 \mathrm{~mA}\end{aligned}$

In the given figure an ammeter A consists of a $240 \Omega$ coil connected in parallel to a $10 \Omega$…

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