In the given circuit, the value of current I L will be _____ mA . (When R L = 1   kΩ )

In the given circuit, the value of current IL will be _____ mA. (When RL=1 )

Solution

Potential drop across the branch containing load resistance will be 5 V due to Zener diode. Therefore, potential drop across 800 Ω will be, 10 V-5 V=5 V.

Now, current through battery will be,

I=5800×1000 =6.25 mA

Current through load will be,

IL=51000 A

=5 mA

Asked in: JEE Main 2022 (24 Jun Shift 2)

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