In the given circuit the sliding contact is pulled outwards such that electric current in the circuit…


In the given circuit the sliding contact is pulled outwards such that electric current in the circuit changes at the rate of $8 \mathrm{~A} / \mathrm{s}$. At an instant when R is $12 \Omega$, the value of the current in the circuit will be ______ A.

Solution

$\begin{aligned} & \varepsilon-\frac{\mathrm{LdI}}{\mathrm{dt}}-\mathrm{IR}=0 \\ & 12-3 \times(-8)-\mathrm{I} \times 12=0 \\ & \mathrm{I}=3\end{aligned}$

Asked in: JEE Main 2025 (23 Jan Shift 1)

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