In the given circuit, the potential difference between $A$ and $B$ is
In the given circuit, the potential difference between $A$ and $B$ is
$0$
5 volt
10 volt
15 volt.
Solution
Here $p-n$ junction is forward biased. If $p-n$ junction is ideal, its resistance is zero. The effective resistance across $A$ and $B$
$=\frac{10 \times 10}{10+10}=5 \mathrm{~K} \Omega$
Current in the circuit
$I=\frac{30}{(10+5) \times 10^3}=\frac{2}{10^3}$
$\therefore$ Current in each arm $=\frac{I}{2}=\frac{1}{10^3} \mathrm{~A}$. Pot. diff. across $A$ and $B$
$=\frac{1}{10^3} \times 10 \times 10^3=10 \mathrm{~V}$
