In the given circuit, the potential difference across $5 \mu \mathrm{~F}$ capacitor is

In the given circuit, the potential difference across $5 \mu \mathrm{~F}$ capacitor is
  1. 48 V
  2. 24 V
  3. 63 V
  4. 21 V

Solution

$\begin{gathered}C_1=5 \mu \mathrm{~F}, \mathrm{C}_2=(4+8+4)=16 \mu \mathrm{~F} \\ \therefore \mathrm{~V}_1=\left(\frac{\mathrm{C}_2}{\mathrm{C}_1+\mathrm{C}_2}\right) \mathrm{V}=\left(\frac{16}{16+5}\right) 63=48 \mathrm{~V}\end{gathered}$

Asked in: AP EAMCET 2024 (18 May Shift 1)

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