In the given circuit, r m s value of current I r m s through the resistor R is :

Question

Aicharya · Accepted Answer

Impedance of the given LCR circuit will be, $Z = \sqrt{R^{2} + {(X_{L} - X_{C})}^{2}} \Rightarrow Z = \sqrt{100^{2} + {(200 - 100)}^{2}}$

$= 100 \sqrt{2} Ω$

Therefore, RMS current can be written as,

$I_{r m s} = \frac{V_{r m s}}{Z} = \frac{200 \sqrt{2}}{100 \sqrt{2}}$

$= 2 A$

Solution