In the given circuit, if the potential at point B is 24 V , the potential at point A is

In the given circuit, if the potential at point B is 24 V , the potential at point A is

1. $-4.8 \mathrm{~V}$
2. $-2.4 \mathrm{~V}$
3. $-12 \mathrm{~V}$
4. $-14.4 \mathrm{~V}$

Solution

From the given circuit, $\therefore \quad I=\frac{36-12}{3+2}=\frac{24}{5} A$

Again, by $k \vee L$, $\begin{aligned} & 24-12-3 \mathrm{I}=\mathrm{V} \\ & \Rightarrow \mathrm{~V}=12-3 \times \frac{24}{5}=-2.4 \mathrm{~V} \end{aligned}$

Asked in: AP EAMCET 2024 (20 May Shift 2)

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