In the given circuit, find the energy stored in the coil at steady state.

Question

Aicharya · Accepted Answer

Given that, a circuit containing 5 resistances with a battery as shown in figure.

Rearranging the circuit, we get a balanced Wheatstone bridge

As $\frac{R_1}{R_2}=\frac{R_3}{R_4}=\frac{2}{5}$ $\therefore$ No current will pass through the inductor coil i.e., $I=0$ Now, energy stored in inductor is $ U=\frac{1}{2} L I^2 $ Hence, $U=0$

In the given circuit, find the energy stored in the coil at steady state.

Solution