In the given circuit diagram, the currents, $I_{1} = - 0.3 A, I_{4} = 0.8 A$ and $I_{5} = 0.4 A,$ are flowing as shown. The currents $I_{2}, I_{3}$ and $I_{6},$ respectively, are:

Question

In the given circuit diagram, the currents,

I_{1} = - 0.3 A, I_{4} = 0.8 A

and

I_{5} = 0.4 A,

are flowing as shown. The currents

I_{2}, I_{3}

and

I_{6},

respectively, are:

Aicharya · Accepted Answer

G i v e n &#160; I 1 = - 0 . 3 A , I 4 = 0 . 8 A , I 5 = 0 . 4 A , i n &#160; s e r i e s &#160; c o n n e c t i o n &#160; c u r r e n t &#160; w i l l &#160; b e &#160; s a m e , &#160; h e n c e &#160; I 5 = I 6 = 0 . 4 A , A c c o r d i n g &#160; t o &#160; k i r c h o f f ' s &#160; j u n c i o n &#160; r u l e , &#160; a l g e b r a i c &#160; s u m &#160; o f &#160; t h e &#160; c u r r e n t s &#160; m e e t i n g &#160; a t &#160; t t h e &#160; j u c t i o n &#160; i s &#160; z e r o . i . e &#160; c u r r e n t s &#160; f l o w i n g &#160; i n t o &#160; t h e &#160; j u n c t i o n &#160; i s &#160; t a k e n &#160; a s &#160; p o s i t i v e &#160; a n d &#160; c u r r e n t &#160; f l o w i n g &#160; o u t &#160; o f &#160; t h e &#160; j u n c t i o n &#160; i s &#160; t a k e n &#160; a s &#160; n e g a t i v e . A t &#160; t h e &#160; j u n c t i o n &#160; R , &#160; - I 4 + I 2 + I 1 = 0 &#8658; - 0 . 8 + I 2 - 0 . 3 = 0 &#8658; I 2 = 1 . 1 A At &#160; junction &#160; Q , &#160; I 6 + I 3 - I 2 - I 1 = 0 &#8658; 0 . 4 + I 3 - 1 . 1 + 0 . 3 = 0 &#8658; I 3 = 1 . 1 - 0 . 7 = 0 . 4 A It is problem of kirchhof's current law. I 6 = 0.4 &#160; A I 3 = 0.8 &#160; A - O . 4 A = 0.4 &#160; A I 2 = 0.8 + 0.3 A = 1.1 &#160; A

In the given circuit diagram, the currents, I 1 = - 0.3   A ,   I 4 = 0.8   A and I 5 = 0…

Solution

In the given circuit diagram, the currents, I 1 = - 0.3 &#8201; A , &#8201; I 4 = 0.8 &#8201; A and I 5 = 0…

Solution

In the given circuit diagram, the currents, I 1 = - 0.3 A , I 4 = 0.8 A and I 5 = 0…