In the given circuit diagram, in the steady state the current through the battery and the charge on the…

In the given circuit diagram, in the steady state the current through the battery and the charge on the capacitor respectively are
  1. 2 A and $3 \mu \mathrm{C}$
  2. $\frac{6}{11} \mathrm{~A}$ and $\frac{12}{7} \mu \mathrm{C}$
  3. 11 A and $3 \mu \mathrm{C}$
  4. zero ampere and $3 \mu \mathrm{C}$

Solution

In steady state, current through capacitor is zero, hence current through $4 \Omega$ resistor becomes zero. $\begin{array}{ll} \therefore & \frac{1}{R_{e q}}=\frac{1}{1}+\frac{1}{2}+\frac{1}{3}=\frac{6+3+2}{6}=\frac{11}{6} \\ \therefore & I=\frac{V}{R_{e q}}=\frac{6 \times 11}{6}=11 \mathrm{~A} \end{array}$ $\therefore \quad$ Charge on capacitor is, $\mathrm{Q}_{\mathrm{C}}=\mathrm{CV}=0.5 \times 6=3 \mu \mathrm{C}$

Asked in: MHT CET 2024 (09 May Shift 1)

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