In the Friedel-Crafts acylation, the electrophile is

In the Friedel-Crafts acylation, the electrophile is
  1. $\mathrm{C}_{6} \mathrm{H}_{5}^{+}$
  2. $\mathrm{AlCl}_{3}^{-}$
  3. $\mathrm{CH}_{3} \mathrm{CO}^{+}$
  4. $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2}^{+}$

Solution

The electrophile is $\mathrm{CH}_{3} \mathrm{CO}^{+} .$ ^

Asked in: JEE-TOPICTESTS-CHEMISTRY

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