In the formula \(X=3 Y Z^{2}, X\) and \(Z\) have the dimensions of capacitance and magnetic induction,…

In the formula \(X=3 Y Z^{2}, X\) and \(Z\) have the dimensions of capacitance and magnetic induction, respectively. The dimensions of \(Y\) in M.K.S system are \(M^{p} L^{q} T^{r} A^{S}\), then the value of \(p \times q \times r \times s\) is

Solution

$\begin{aligned} Y &=\frac{X}{3 Z^{2}}=\frac{1}{3} \frac{Q^{2}}{W} \times \frac{I^{2} L^{2}}{F^{2}} \\ &=\frac{A^{2} T^{2} A^{2} L^{2}}{\left[M L^{2} T^{-2}\right]\left[M^{2} L^{2} T^{-4}\right]}=\left[M^{-3} L^{-2} T^{8} A^{4}\right] \end{aligned}$

Asked in: JEE Mains - Units and Dimensions - Chapter Test

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