In the formula for resolving power of microscope, the numerical aperture is represented by
- $\frac{2 \mu \sin \alpha}{\lambda}$
- $\frac{2 \sin \alpha}{\mu \lambda}$
- $\mu \sin \alpha$
- $\frac{\lambda}{2 \mu \sin \alpha}$
Solution
Asked in: MHT CET 2020 (15 Oct Shift 1)