In the following unbalanced reaction, the product formed is $\mathrm{Al}_2 \mathrm{O}_3+\mathrm{NaOH}(a…

In the following unbalanced reaction, the product formed is $\mathrm{Al}_2 \mathrm{O}_3+\mathrm{NaOH}(a q)+\mathrm{H}_2 \mathrm{O} \longrightarrow$
  1. $\mathrm{Na}_3\left[\mathrm{Al}(\mathrm{OH})_6\right]$
  2. $\mathrm{Na}_3\left[\mathrm{Al}(\mathrm{OH})_4\right]$
  3. $\mathrm{Na}_2\left[\mathrm{Al}(\mathrm{OH})_5\right]$
  4. $\mathrm{Na}\left[\mathrm{Al}(\mathrm{OH})_6\right]$

Solution

Aluminium oxide reacts with aqueous solution of sodium hydroxide to form sodium hexahydroxyaluminate (III). $\mathrm{Al}_2 \mathrm{O}_3+\mathrm{NaOH}+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Na}_3\left[\mathrm{Al}(\mathrm{OH})_6\right]$

Asked in: AP EAMCET 2022 (07 Jul Shift 1)

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