In the following skew conformation of ethane, H ' - C - C - H ″ dihedral angle is:

In the following skew conformation of ethane, H'-C-C-H dihedral angle is:
  1. 58o
  2. 120o
  3. 149o
  4. 151o

Solution

The structure given in question is in staggered form. Hence, the two planes are $120^{\circ}$ apart. Given difference in angle of $H-C-H$ bond is $29$. Therefore, the dihedral angle will be $120^{\circ} + 29^{\circ} = 149^{\circ}$.

Asked in: JEE Main 2019 (12 Apr Shift 2)

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