In the following sequence of reactions, the alkene affords the compound B . CH 3 CH = CHCH 3 ⟶ O 3 A…

1. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CHO}$
2. ${\mathrm{CH}}_3{\mathrm{COCH}}_3$
3. ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{COCH}}_3$
4. ${\mathrm{CH}}_3\mathrm{CHO}$

Solution

The complete reaction sequence is as follows:

Asked in: MHT CET 2023 (14 May Shift 2)

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