Chemistry › Chemical Kinetics › Rate law and rate constant
In the following reaction; xA→yB
log10-dAdt=log10-dBdt+0.3010
‘A’ and ‘B’ respectively can be:
From the rate law:
log-dAdt=logdBdt+0.3010=log-dAdt=logdBdt+log2
-dAdt=2×dBdt
2A→B and we know 2C2H4→C4H8
Asked in: JEE Main 2019 (12 Apr Shift 1)
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