In the following reaction, $\mathrm{I}_2+\mathrm{H}_2 \mathrm{O}+\mathrm{Cl}_2 \longrightarrow X+Y$, the…
In the following reaction, $\mathrm{I}_2+\mathrm{H}_2 \mathrm{O}+\mathrm{Cl}_2 \longrightarrow X+Y$, the products $X$ and $Y$ respectively are
$\mathrm{HClO}_4, \mathrm{HI}$
$\mathrm{I}_2 \mathrm{O}_7, \mathrm{HCl}$
$\mathrm{HIO}_3, \mathrm{HCl}$
$\mathrm{ICl}_3, \mathrm{HCl}$
Solution
The products $X$ and $Y$ are $\mathrm{HIO}_3$ and $\mathrm{HCl}$ respectively. Balanced equation is as follows
$
\mathrm{I}_2+5 \mathrm{Cl}_2+6 \mathrm{H}_2 \mathrm{O} \longrightarrow \underset{\text { Iodic acid }}{2 \mathrm{HIO}_3}+10 \mathrm{HCl}
$