In the following reaction sequence, the compound $\mathrm{J}$ is an intermediate.…

In the following reaction sequence, the compound $\mathrm{J}$ is an intermediate.
$\mathbf{J}\left(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{2}\right)$ gives effervescence on treatment with $\mathrm{NaHCO}_{3}$ and a positive Baeyer's test. Question: The compound $\mathbf{I}$ is

Asked in: JEE Advanced 2012 (Paper 2)

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