In the following reaction. $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OC}_{2} \mathrm{H}_{5}+4 \mathrm{H}…

In the following reaction.
$\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OC}_{2} \mathrm{H}_{5}+4 \mathrm{H} \stackrel{\text { Red } \mathrm{P}+\mathrm{HI}}{\longrightarrow} 2 \mathrm{X}+\mathrm{H}_{2} \mathrm{O}$;
$X$ is
  1. ethane
  2. ethylene
  3. butane
  4. propane

Solution

Ethers are reduced by red $\mathrm{P}$ and HI to alkanes through alkyl iodides
$\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OC}_{2} \mathrm{H}_{5} \stackrel{\text { red P+HI }}{\longrightarrow} 2 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I} \stackrel{\text { red P+HI }}{\longrightarrow} 2 \mathrm{C}_{2} \mathrm{H}_{6}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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