
In the following circuit, the reading in the ammeter is

- 25.1 mA
- 22.5 mA
- 21.5 mA
- 21.25 mA
Solution
For silicon diode, $\mathrm{V}_{\text {diode }}=0.7 \mathrm{~V}$ $\therefore \quad \mathrm{I}=\frac{5-0.7}{200}=\frac{4.3}{200}=21.5 \mathrm{~mA}$
Asked in: MHT CET 2024 (09 May Shift 2)