In the following circuit, the output $\mathrm{Y}$ for all possible inputs $\mathrm{A}$ and $\mathrm{B}$ is expressed by the truth table.

Question

Aicharya · Accepted Answer

$Y^{\prime}=\overline{A+B} . \quad Y=\overline{\overline{A+B}}=A+B$ Truth table of the given circuit is given by $\begin{array}{|c|c|c|c|} \hline A & B & Y^{\prime} & Y \ \hline 0 & 0 & 1 & 0 \ \hline 0 & 1 & 0 & 1 \ \hline 1 & 0 & 0 & 1 \ \hline 1 & 1 & 0 & 1 \ \hline \end{array}$

In the following circuit, the output $\mathrm{Y}$ for all possible inputs $\mathrm{A}$ and $\mathrm{B}$ is…

Solution