In the following circuit, the equivalent capacitance between terminal $A$ and terminal $B$ is :

In the following circuit, the equivalent capacitance between terminal $A$ and terminal $B$ is :

1. $1 \mu \mathrm{F}$
2. $0.5 \mu \mathrm{F}$
3. $4 \mu \mathrm{F}$
4. $2 \mu \mathrm{F}$

Solution

Given circuit is balanced Wheatstone bridge
$\begin{aligned} C_{A B} & =1+1 \\ & =2 \mu F\end{aligned}$ ~

Asked in: NEET 2024

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