In the following balanced reaction, $\mathrm{XMnO}_{4}^{-}+\mathrm{Y} \mathrm{C}_{2}…

In the following balanced reaction, $\mathrm{XMnO}_{4}^{-}+\mathrm{Y} \mathrm{C}_{2} \mathrm{O}_{4}^{2-}+\mathrm{ZH}^{+} ightleftharpoons \mathrm{XMn}^{2+}+2 \mathrm{Y} \mathrm{CO}_{2}+\frac{\mathrm{Z}}{2} \mathrm{H}_{2} \mathrm{O}$ values of $X, Y$ and $Z$ respectively are
  1. $2,5,16$
  2. $8,2,5$
  3. $5,2,16$
  4. $5,8,4$

Solution

$\mathrm{X} \mathrm{MnO}_{4}^{-}+\mathrm{Y} \mathrm{C}_{2} \mathrm{O}_{4}^{2-}+\mathrm{ZH}^{+} \leftrightharpoons \mathrm{X} \mathrm{Mn}^{+2}+2 \mathrm{Y} \mathrm{CO}_{2}+\frac{\mathrm{Z}}{2} \mathrm{H}_{2} \mathrm{O}$
First half reaction $\mathrm{MnO}_{4}^{-} \longrightarrow \mathrm{Mn}^{+2} \ldots$(i)
On balancing
$\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+}+5 \mathrm{e}^{-} \longrightarrow \mathrm{Mn}^{+2}+4 \mathrm{H}_{2} \mathrm{O}$...(ii)
Second half reaction
$\mathrm{C}_{2} \mathrm{O}_{4}^{2-} \longrightarrow 2 \mathrm{CO}_{2}$...(iii)
On balancing
$\mathrm{C}_{2} \mathrm{O}_{4}^{2-} \longrightarrow 2 \mathrm{CO}_{2}+2 \mathrm{e}^{-}$...(iv)
On multiplying eqn. (ii) by 5 and (iv) by 2 and then adding we get
$2 \mathrm{MnO}_{4}^{-}+5 \mathrm{C}_{2} \mathrm{O}_{4}^{2-}+16 \mathrm{H}^{+} \longrightarrow 2 \mathrm{Mn}^{+2}+10 \mathrm{CO}_{2}+8 \mathrm{H}_{2} \mathrm{O}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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