In the figure shown below, the charge on the left plate of the 10F capacitor is -30C. The charge on the…

In the figure shown below, the charge on the left plate of the 10F capacitor is -30C. The charge on the right plate of the 6F capacitor is:

1. $-12 \mu \mathrm{C}$
2. $+12 \mu \mathrm{C}$
3. $-18 \mu \mathrm{C}$
4. $+18 \mu \mathrm{C}$

Solution

As given in the figure, $6 \mu \mathrm{F}$ and $4 \mu \mathrm{F}$ are in parallel. Now using charge conservation Charge on $6 \mu F$ capacitor $=\frac{6}{6+4} \times 30=18 \mu C$ Since charge is asked on right plate therefore is $+18 \mu C$

Asked in: JEE Main 2019 (11 Jan Shift 1)

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