In the figure shown A B C is a uniform wire. If the center of mass of the wire lies vertically below point A…

In the figure shown ABC is a uniform wire. If the center of mass of the wire lies vertically below point A, then BCAB is close to

  1. 1.85
  2. 1.5
  3. 1.37
  4. 3

Solution



xcm=x2=(ρx)(x2)12+ρy(y2)ρ(x+y)

⇒  12+yx=y2x2

⇒  yx=1+32=1.37

Asked in: JEE Main 2016 (10 Apr Online)

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