In the electrolysis of $\mathrm{CuCl}_{2}$ solution, the mass of the cathode increased by $3.2 \mathrm{~g}$.…
- $0.12$ litre of $\mathrm{Cl}_{2}$ was liberated
- $0.56$ litre of $\mathrm{O}_{2}$ was liberated
- $0.1 \mathrm{~mol} \mathrm{Cu}^{2+}$ passed into the solution.
- $0.05 \mathrm{~mol}$ of $\mathrm{Cu}^{2+}$ passed into the solution.
Solution
The same amount $0.05$ mole of $\mathrm{Cu}^{2+}$ must pass into solution from anode by oxidation
Asked in: JEE-TOPICTESTS-CHEMISTRY