In the decay sequence: U 92 238 → - x 1 T h 90 234 → - x 2 P a 91 234 → - x 3 Z   234 → - x 4 T h 90 230 x 1 ,   x 2 ,   x 3 and x 4 are the particles/ radiation emitted by the respective isotopes. The correct option(s) is/are:

Question

In the decay sequence: U 92 238 &#8594; - x 1 T h 90 234 &#8594; - x 2 P a 91 234 &#8594; - x 3 Z &#160; 234 &#8594; - x 4 T h 90 230 x 1 , &#160; x 2 , &#160; x 3 and x 4 are the particles/ radiation emitted by the respective isotopes. The correct option(s) is/are:

Aicharya · Accepted Answer

${ }_{92}^{238} U \xrightarrow{{ }_2 H e^4}{ }_{90}^{234} \mathrm{Th} \xrightarrow{{ }_{-1} e^o}{ }_{91}^{234} \mathrm{~Pa} \xrightarrow{{ }_{-1} e^o}{ }_{92}^{234} Z \xrightarrow{{ }_2 \mathrm{He}^4}{ }_{90}^{230} \mathrm{Th}$ $x_1=\alpha$ since positively charged so, will attracted by negative plate. $x_2=\beta$ negatively charged and attracted by positive plate $x_3=\beta$ negatively charged and attracted by positive plate $x_4=\alpha$ since positively charged so, will attracted by negative plate. $\mathrm{U}$ and $\mathrm{Z}$ have the same atomic number so they are isotope.

In the decay sequence: U 92 238 → - x 1 T h 90 234 → - x 2 P a 91 234 → - x 3 Z   234…

Solution

In the decay sequence: U 92 238 &#8594; - x 1 T h 90 234 &#8594; - x 2 P a 91 234 &#8594; - x 3 Z &#160; 234…

Solution

In the decay sequence: U 92 238 → - x 1 T h 90 234 → - x 2 P a 91 234 → - x 3 Z 234…