In the constructed triangle, $XB + BC + CY$ equals

In the constructed triangle, $XB + BC + CY$ equals
  1. perimeter $= AB + BC + AC$
  2. $2 \times$ perimeter
  3. $AB$
  4. $AC$

Solution

$XB = AB$, $YC = AC$, so $XB + BC + CY = AB + BC + AC$.

Asked in: MH-SSC-9

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