In the combination of the following gates the output Y can be written in terms of inputs A and B as

In the combination of the following gates the output $Y$ can be written in terms of inputs $A$ and $B$ as

1. $\overline{A.B}+A.B$
2. $\overline{A+B}$
3. $A.\overline{B}+\overline{A}.B$
4. $\overline{A.B}$

Solution

$Y=\left(A.\overline{B}+\overline{A}.B\right)$

Asked in: NEET 2018

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