In the Claisen-Schmidt reaction to prepare, dibenzalacetone from 5.3 g of benzaldehyde, a total of 3.51 g of…
Solution

$\begin{aligned} & \text { Theoretical }=\frac{1}{40} \mathrm{Mol} \\ & \% \text { yield }=\frac{0.015}{1 / 40} \times 100 \\ & \Rightarrow 60 \%\end{aligned}$
Asked in: JEE Main 2025 (29 Jan Shift 2)
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