In the circuit shown in the following figure, the potential difference cross $3 \mu \mathrm{~F}$ capacitor is

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Aicharya · Accepted Answer

$\begin{aligned} & V_{e q}=20-4 \ & =16 \mathrm{~V} \ & \mathrm{C}_{\mathrm{eq}}=\frac{3 	imes 5}{3+5} \ & =\frac{15}{8} \ & \mathrm{Q}=\mathrm{C}_{\mathrm{eq}} 	imes \mathrm{V}_{\mathrm{eq}} \ & =\frac{15}{8} 	imes 16 \ & =30 \mathrm{C} \ & \dot{\mathrm{~V}}_3=\frac{\mathrm{Q}}{\mathrm{C}}=\frac{30}{3}=10 \mathrm{~V} \end{aligned}$ .

In the circuit shown in the following figure, the potential difference cross $3 \mu \mathrm{~F}$ capacitor is

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