In the circuit shown in the figure, the total charge is 750   μ C and the voltage across capacitor…

In the circuit shown in the figure, the total charge is 750 μC and the voltage across capacitor C2 is 20 V. Then the charge on capacitor C2 is :
  1. 450 μC
  2. 590 μC
  3. 160 μC
  4. 650 μC

Solution

Applying Kirchoff's law we get,

q2+q3=750

q2+160=750

q2=590 μC

Asked in: JEE Main 2020 (03 Sep Shift 1)

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