In the circuit shown in figure, if the diode forward voltage is $0.3 \mathrm{~V}$, the voltage difference…
In the circuit shown in figure, if the diode forward voltage is $0.3 \mathrm{~V}$, the voltage difference between $A$ and $B$ is
$1.3 \mathrm{~V}$
$2.3 \mathrm{~V}$
$0$
$0.5 \mathrm{~V}$
Solution
Let $V$ be the potential difference between $A$ and $B$, then
$\begin{array}{ll} & V-0.3=(5+5) \times 10^3 \times\left(0.2 \times 10^{-3}\right)=2 \\ \text { or } & V=2+0.3=2.3 \mathrm{~V}\end{array}$
