In the circuit shown, charge on the 5 μ F capacitor is :

In the circuit shown, charge on the 5μF  capacitor is :

  1. 18.00μC
  2. 10.90μC
  3. 16.36μC
  4. 5.45μC

Solution

VB=6  VC=x  VD=6

-91+92+93=0
-2(6-x)+4(x-6)+5(x-0)=0
-12+2 x+4 x-24+5 x=0
11x=36⇒x=3611;q3=5×3611=18011μC

Asked in: JEE Main 2020 (05 Sep Shift 2)

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