In the case of photoelectric emission from a certain metal, the cutoff frequency is $v$. If radiation of…
In the case of photoelectric emission from a certain metal, the cutoff frequency is $v$. If radiation of frequency $2 v$ is incident on the metal plate, the maximum possible velocity of the emitted electrons will be ( $m=$ mass of electron)
$2 \sqrt{\frac{h v}{m}}$
$\sqrt{\frac{h v}{2 m}}$
$\sqrt{\frac{2 h v}{m}}$
$\sqrt{\frac{h v}{m}}$
Solution
$K \cdot E .=E-\phi$
$\frac{1}{2} m v_{\max }^2=h(2 v)-h v$
$v_{\max }=\sqrt{\frac{2 h v}{m}}$
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