In the binomial expansion of $(a-b)^n, n \geq 5$, the sum of the $5^{ ext {th }}$ and $6^{ ext {th }}$ terms is zero. Then the value of $\frac{a}{b}$ is

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In the binomial expansion of $(a-b)^n, n \geq 5$, the sum of the $5^{	ext {th }}$ and $6^{	ext {th }}$ terms is zero. Then the value of $\frac{a}{b}$ is

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In the binomial expansion of $(a-b)^n, n \geq 5$, the sum of the $5^{\text {th }}$ and $6^{\text {th }}$…

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