$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH} \underset{\text { Red }…
$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH} \underset{\text { Red } \mathrm{P}}{\stackrel{\mathrm{Br}_{2}}{\longrightarrow} \mathrm{X}} \stackrel{\mathrm{NH}_{3} \text { (alc.) }}{\longrightarrow} \mathrm{Y}$
$\mathrm{Y}$ in the above reactions is
- lactic acid
- ethylamine
- propylamine
- alanine
Solution
$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH} \stackrel{\mathrm{red} \mathrm{P}, \mathrm{Br}_{2}}{\longrightarrow} \mathrm{CH}_{3} \mathrm{CHBr} \mathrm{COOH} \stackrel{\mathrm{NH}_{3}}{\longrightarrow} \underset{\alpha-\text { Aminopropionic acid (alanine) }}{\mathrm{CH}_{3} \mathrm{CHNH}_{2} \mathrm{COOH}}$
Asked in: JEE-TOPICTESTS-CHEMISTRY
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