$\begin{aligned} \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}+4 \mathrm{I}_2+ & 3 \mathrm{Na}_2 \mathrm{CO}_3…
$\begin{aligned} \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}+4 \mathrm{I}_2+ & 3 \mathrm{Na}_2 \mathrm{CO}_3 \longrightarrow \\ & \mathrm{X}+\mathrm{HCOONa}+5 \mathrm{NaI}+3 \mathrm{CO}_2+2 \mathrm{H}_2 \mathrm{O}\end{aligned}$
In the above reaction, ' $X$ ' is
- diiodomethane
- triiodomethane
- iodomethane
- tetraiodomethane
Solution
\(\mathrm{C}_2 \mathrm{H}_6 \mathrm{OH}+4 \mathrm{I}_2+3 \mathrm{Na}_2 \mathrm{CO}_3 \longrightarrow \underset{\text{Triiodomethane}}{\mathrm{CHI}_3} + \underset{\text{Sodium formate}}{\mathrm{HCOONa}}+5 \mathrm{NaI}+3 \mathrm{CO}_2+2 \mathrm{H}_2 \mathrm{O}\)
Asked in: TEST SERIES MHT-CET Full Test 6
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