In sulphur estimation. 0 . 471   g of an organic compound gave 1 . 4439   g of barium sulphate.…

In sulphur estimation. 0.471 g of an organic compound gave 1.4439 g of barium sulphate. The percentage of sulphur in the compound is _______(Nearest Integer)

(Given: Atomic mass Ba: 137u:S:32u,O:16u )

Solution

Molecular mass of Barium Sulphate(BaSO4) = 233 g
%sulphur=32233× weight of BaSO4 formed  weight of organic compound ×100

=32233×1.44390.471×100

=42.10

Nearest integer: 42

Asked in: JEE Main 2023 (25 Jan Shift 1)

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