In   S I units, the dimensions of ϵ 0 μ 0 is:

In  SI units, the dimensions of ϵ0μ0 is:
  1.  AT2M-1L-1
  2.  A2T3M-1L-2
  3. A-1TML3
  4. AT-3ML3/2

Solution

As we know, c=1μ0ε0
 ε0μ0=ε02μ0ε0=ε0c
ε0μ0= ε0c=M-1L-3T4A2[LT-1]
=[M-1L-2T3A2]

Asked in: JEE Main 2019 (08 Apr Shift 1)

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