In S.I. system, the total energy of the free surface of a liquid drop is $2 \pi$ times the surface tension…
- $\sqrt{3} \mathrm{~m}$
- $\sqrt{2} \mathrm{~m}$
- $\sqrt{5} \mathrm{~m}$
- $\sqrt{7} \mathrm{~m}$
Solution
Asked in: AP EAMCET 2017 (26 Apr Shift 2)
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