In S.H.M. a simple pendulum oscillates with frequency $f$. If the length of the pendulum is increased by…
In S.H.M. a simple pendulum oscillates with frequency $f$. If the length of the pendulum is increased by three times its original length, then the frequency of oscillation of the pendulum will be
$4 f$
$2 f$
$f$
$\frac{f}{2}$
Solution
$T \propto \sqrt{l}$ or $f \propto 1 / \sqrt{l}$
If the length is increased by three times the original length, then the new length is four times the original length.
$\frac{f_1}{f}=\sqrt{\frac{l}{4 l}}=\frac{1}{2}$
.