In second period of the long form of the periodic table, an element X has second lowest first ionization…
In second period of the long form of the periodic table, an element has second lowest first ionization enthalpy and element has second highest first ionization enthalpy values. What are and ?
Solution
The order of ionization enthalpy of elements of 2nd period in long form of periodic table is \(\mathrm{Li} < \mathrm{B} < \mathrm{Be} < \mathrm{C} < \mathrm{O} < \mathrm{N} < \mathrm{F} < \mathrm{Ne}\).
Generally, on going left to right in a period, ionization energy increases, but there are some exceptions to this. For example, Be has more ionization energy than \(\mathrm{B}\), due to fulfilled s-orbital. And \(\mathrm{N}\) has more ionization energy than \(\mathrm{O}\) due to half filled p-subshell.
So,In second period of the long form of the periodic table, the element B has second lowest first ionization enthalpy and element F has second highest first ionization enthalpy values.
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