In $\mathrm{P}^{\text {th }}$ second, a particle describes angular displacement of ' $\beta$ ' rad. If it…
In $\mathrm{P}^{\text {th }}$ second, a particle describes angular displacement of ' $\beta$ ' rad. If it starts from rest, the angular acceleration is
$\frac{\beta}{P}$
$\frac{\beta}{(P-1)}$
$\frac{2 \beta}{(2 P-1)}$
$\frac{(2 \beta+1)}{(2 \mathrm{P}-1)}$
Solution
The equation for the angular displacement of the particle that starts from rest is given as:
$\beta=0+\frac{1}{2} \alpha(2 \mathrm{P}-1)$
$\therefore \quad$ The angular acceleration of the particle is $\alpha=\frac{2 \beta}{(2 \mathrm{P}-1)}$