In rhombus $ABCD$, the diagonals are $24$ cm and $10$ cm. The area of the rhombus is:

In rhombus $ABCD$, the diagonals are $24$ cm and $10$ cm. The area of the rhombus is:
  1. $60$ cm$^{2}$
  2. $120$ cm$^{2}$
  3. $240$ cm$^{2}$
  4. $340$ cm$^{2}$

Solution

Area of a rhombus $= \dfrac{1}{2} d_{1} d_{2} = \dfrac{1}{2} \cdot 24 \cdot 10 = 120$ cm$^{2}$.

Asked in: IMO

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