In respiration from $180 \mathrm{~g}$ of glucose which of the following is formed?

In respiration from $180 \mathrm{~g}$ of glucose which of the following is formed?
  1. 264gm $\mathrm{CO}_2+190 \mathrm{gm} \mathrm{H}_2 \mathrm{O}+391 \mathrm{Kcal}$
  2. $264 \mathrm{gm} \mathrm{CO}_2 +108 \mathrm{gm} \mathrm{H}_2 \mathrm{O}+686 \mathrm{Kcal}$
  3. $390 \mathrm{gm} \mathrm{CO}_2 +108 \mathrm{gm} \mathrm{H}_2 \mathrm{O}+686 \mathrm{Kcal}$
  4. $390 \mathrm{gm} \mathrm{CO}_2+264 \mathrm{gm} \mathrm{H}_2 \mathrm{O}+391 \mathrm{Kcal}$

Solution

In respiration, from $180 \mathrm{gm}$ of glucose 264 $\mathrm{gm} \mathrm{CO} \mathrm{CO}_2+108 \mathrm{gm} \mathrm{H}_2 \mathrm{O}+686 \mathrm{Kcal}$ energy is formed. $\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6+6 \mathrm{O}_2 \rightarrow 6 \mathrm{CO}_2+6 \mathrm{H}_2 \mathrm{O}+686 \mathrm{Kcal}$ Atomic weight of $\mathrm{C}=12, \mathrm{H}=1, \mathrm{O}=16$ $\begin{aligned} \mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6 & =(12 \times 6+12 \times 1+16 \times 6) \\ & =180 \mathrm{gm} \\ 6 \mathrm{CO}_2 & =6(12+16 \times 2) \\ & =264 \mathrm{gm} \\ 6 \mathrm{H}_2 \mathrm{O} & =6(2 \times 1+16) \\ & =108 \mathrm{gm} \end{aligned}$ $\therefore$ From $1 \mathrm{molecule}$ or $180 \mathrm{gm}$ of glucose, through energy are formed.

Asked in: NEET 2011 (Screening)

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