In quadrilateral $ABCD$, $\angle A = 80^{\circ}, \angle B = 100^{\circ}, \angle C = 80^{\circ}, \angle D =…
In quadrilateral $ABCD$, $\angle A = 80^{\circ}, \angle B = 100^{\circ}, \angle C = 80^{\circ}, \angle D = 100^{\circ}$. $ABCD$ is
- a parallelogram
- a kite
- a trapezium only
- a square
Solution
Both opposite angle pairs equal.
Asked in: MH-SSC-9
Practice more Quadrilaterals questions on Aicharya