In quadrilateral $ABCD$, $AB = CD$ and $AD = BC$. Then $ABCD$ is a

In quadrilateral $ABCD$, $AB = CD$ and $AD = BC$. Then $ABCD$ is a
  1. parallelogram
  2. square only
  3. rhombus only
  4. trapezium

Solution

Both pairs of opposite sides equal.

Asked in: MH-SSC-9

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