In potentiometer experiment, cells of e.m.f. ' $E_1$ ' and ' $E_2$ ' are connected in series $\left(E_1E_2\right)$ the balancing length is $64 \mathrm{~cm}$ of the wire. If the polarity of $\mathrm{E}_2$ is reversed, the balancing length becomes $32 \mathrm{~cm}$. The ratio $\frac{E_1}{E_2}$ is

Question

In potentiometer experiment, cells of e.m.f. ' $E_1$ ' and ' $E_2$ ' are connected in series $\left(E_1>E_2\right)$ the balancing length is $64 \mathrm{~cm}$ of the wire. If the polarity of $\mathrm{E}_2$ is reversed, the balancing length becomes $32 \mathrm{~cm}$. The ratio $\frac{E_1}{E_2}$ is

Aicharya · Accepted Answer

$\frac{E_1}{E_2}=\frac{\ell_1+\ell_2}{\ell_1-\ell_2}=\frac{64+32}{64-32}=\frac{96}{32}=3$

In potentiometer experiment, cells of e.m.f. ' $E_1$ ' and ' $E_2$ ' are connected in series…

Solution